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  • Trivia Friday (19072024)

    Posted by Renita DSouza on July 19, 2024 at 4:42 pm

    A team decides to build an accumulator using lithium-ion cells (Nominal Voltage: 3.7V, Max Charge Voltage: 4.2V, Capacity: 2.2Ah @1C, Internal Impedance: <=42 mohm) arranged in a 10p100s configuration. The team selects a fuse rated at 125A, as per the curve in the datasheet. Theoretically, how long (in seconds) will it take for the fuse to blow if the positive and negative terminals of the fully charged battery pack are shorted with a wire having negligible resistance?

    a) 0.5

    b) 0.6

    c ) 0.7

    d) 0.8

    Renita DSouza replied 3 months, 3 weeks ago 9 Members · 9 Replies
  • 9 Replies
  • Lakshma Narayanan J B

    Member
    July 19, 2024 at 4:44 pm

    a)0.5

  • Jeeva K

    Member
    July 19, 2024 at 5:02 pm

    B

  • Himanshu Singh

    Member
    July 19, 2024 at 5:07 pm

    C

  • Aryan Baviskar

    Member
    July 19, 2024 at 5:08 pm

    D) 0.8

  • Karthi S

    Member
    July 19, 2024 at 5:14 pm

    C

  • ANUBHAV MAITY

    Member
    July 19, 2024 at 5:22 pm

    B

  • AMRIT CHIRANIA

    Member
    July 19, 2024 at 5:22 pm

    B

  • Ankit

    Member
    July 19, 2024 at 8:32 pm

    The shortest time among the options is 0.5 Milliseconds. So, the option is a) 0.5.

    There is no calculation for this Question.

  • Renita DSouza

    Administrator
    July 20, 2024 at 12:30 pm

    The correct answer is b) 0.6. The winner of this week’s trivia is Jeeva K.

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